Optimal. Leaf size=668 \[ \frac{\left (a^2 f \left (e^2 \sqrt{e^2-4 d f}-d f \sqrt{e^2-4 d f}-3 d e f+e^3\right )+2 a c d^2 f \left (\sqrt{e^2-4 d f}+e\right )+c^2 d^3 \left (e-\sqrt{e^2-4 d f}\right )\right ) \tanh ^{-1}\left (\frac{2 a f-c x \left (e-\sqrt{e^2-4 d f}\right )}{\sqrt{2} \sqrt{a+c x^2} \sqrt{2 a f^2+c \left (-e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}\right )}{\sqrt{2} d^3 \sqrt{e^2-4 d f} \sqrt{2 a f^2+c \left (-e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}-\frac{\left (a^2 f \left (-e^2 \sqrt{e^2-4 d f}+d f \sqrt{e^2-4 d f}-3 d e f+e^3\right )+2 a c d^2 f \left (e-\sqrt{e^2-4 d f}\right )+c^2 d^3 \left (\sqrt{e^2-4 d f}+e\right )\right ) \tanh ^{-1}\left (\frac{2 a f-c x \left (\sqrt{e^2-4 d f}+e\right )}{\sqrt{2} \sqrt{a+c x^2} \sqrt{2 a f^2+c \left (e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}\right )}{\sqrt{2} d^3 \sqrt{e^2-4 d f} \sqrt{2 a f^2+c \left (e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}-\frac{a^{3/2} \left (e^2-d f\right ) \tanh ^{-1}\left (\frac{\sqrt{a+c x^2}}{\sqrt{a}}\right )}{d^3}+\frac{a \sqrt{a+c x^2} \left (e^2-d f\right )}{d^3}-\frac{\sqrt{a+c x^2} \left (2 \left (a \left (e^2-d f\right )+c d^2\right )-c d e x\right )}{2 d^3}+\frac{e \left (a+c x^2\right )^{3/2}}{d^2 x}-\frac{3 c e x \sqrt{a+c x^2}}{2 d^2}-\frac{\left (a+c x^2\right )^{3/2}}{2 d x^2}+\frac{3 c \sqrt{a+c x^2}}{2 d}-\frac{3 \sqrt{a} c \tanh ^{-1}\left (\frac{\sqrt{a+c x^2}}{\sqrt{a}}\right )}{2 d} \]
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Rubi [A] time = 3.46473, antiderivative size = 668, normalized size of antiderivative = 1., number of steps used = 26, number of rules used = 15, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.556, Rules used = {6728, 266, 47, 50, 63, 208, 277, 195, 217, 206, 1020, 1068, 1080, 1034, 725} \[ \frac{\left (a^2 f \left (e^2 \sqrt{e^2-4 d f}-d f \sqrt{e^2-4 d f}-3 d e f+e^3\right )+2 a c d^2 f \left (\sqrt{e^2-4 d f}+e\right )+c^2 d^3 \left (e-\sqrt{e^2-4 d f}\right )\right ) \tanh ^{-1}\left (\frac{2 a f-c x \left (e-\sqrt{e^2-4 d f}\right )}{\sqrt{2} \sqrt{a+c x^2} \sqrt{2 a f^2+c \left (-e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}\right )}{\sqrt{2} d^3 \sqrt{e^2-4 d f} \sqrt{2 a f^2+c \left (-e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}-\frac{\left (a^2 f \left (-e^2 \sqrt{e^2-4 d f}+d f \sqrt{e^2-4 d f}-3 d e f+e^3\right )+2 a c d^2 f \left (e-\sqrt{e^2-4 d f}\right )+c^2 d^3 \left (\sqrt{e^2-4 d f}+e\right )\right ) \tanh ^{-1}\left (\frac{2 a f-c x \left (\sqrt{e^2-4 d f}+e\right )}{\sqrt{2} \sqrt{a+c x^2} \sqrt{2 a f^2+c \left (e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}\right )}{\sqrt{2} d^3 \sqrt{e^2-4 d f} \sqrt{2 a f^2+c \left (e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}-\frac{a^{3/2} \left (e^2-d f\right ) \tanh ^{-1}\left (\frac{\sqrt{a+c x^2}}{\sqrt{a}}\right )}{d^3}+\frac{a \sqrt{a+c x^2} \left (e^2-d f\right )}{d^3}-\frac{\sqrt{a+c x^2} \left (2 \left (a \left (e^2-d f\right )+c d^2\right )-c d e x\right )}{2 d^3}+\frac{e \left (a+c x^2\right )^{3/2}}{d^2 x}-\frac{3 c e x \sqrt{a+c x^2}}{2 d^2}-\frac{\left (a+c x^2\right )^{3/2}}{2 d x^2}+\frac{3 c \sqrt{a+c x^2}}{2 d}-\frac{3 \sqrt{a} c \tanh ^{-1}\left (\frac{\sqrt{a+c x^2}}{\sqrt{a}}\right )}{2 d} \]
Antiderivative was successfully verified.
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Rule 6728
Rule 266
Rule 47
Rule 50
Rule 63
Rule 208
Rule 277
Rule 195
Rule 217
Rule 206
Rule 1020
Rule 1068
Rule 1080
Rule 1034
Rule 725
Rubi steps
\begin{align*} \int \frac{\left (a+c x^2\right )^{3/2}}{x^3 \left (d+e x+f x^2\right )} \, dx &=\int \left (\frac{\left (a+c x^2\right )^{3/2}}{d x^3}-\frac{e \left (a+c x^2\right )^{3/2}}{d^2 x^2}+\frac{\left (e^2-d f\right ) \left (a+c x^2\right )^{3/2}}{d^3 x}+\frac{\left (-e \left (e^2-2 d f\right )-f \left (e^2-d f\right ) x\right ) \left (a+c x^2\right )^{3/2}}{d^3 \left (d+e x+f x^2\right )}\right ) \, dx\\ &=\frac{\int \frac{\left (-e \left (e^2-2 d f\right )-f \left (e^2-d f\right ) x\right ) \left (a+c x^2\right )^{3/2}}{d+e x+f x^2} \, dx}{d^3}+\frac{\int \frac{\left (a+c x^2\right )^{3/2}}{x^3} \, dx}{d}-\frac{e \int \frac{\left (a+c x^2\right )^{3/2}}{x^2} \, dx}{d^2}+\frac{\left (e^2-d f\right ) \int \frac{\left (a+c x^2\right )^{3/2}}{x} \, dx}{d^3}\\ &=-\frac{\left (e^2-d f\right ) \left (a+c x^2\right )^{3/2}}{3 d^3}+\frac{e \left (a+c x^2\right )^{3/2}}{d^2 x}+\frac{\operatorname{Subst}\left (\int \frac{(a+c x)^{3/2}}{x^2} \, dx,x,x^2\right )}{2 d}-\frac{(3 c e) \int \sqrt{a+c x^2} \, dx}{d^2}+\frac{\int \frac{\sqrt{a+c x^2} \left (-3 a e f \left (e^2-2 d f\right )+3 f (c d-a f) \left (e^2-d f\right ) x+3 c d e f^2 x^2\right )}{d+e x+f x^2} \, dx}{3 d^3 f}+\frac{\left (e^2-d f\right ) \operatorname{Subst}\left (\int \frac{(a+c x)^{3/2}}{x} \, dx,x,x^2\right )}{2 d^3}\\ &=-\frac{3 c e x \sqrt{a+c x^2}}{2 d^2}-\frac{\left (2 \left (c d^2+a \left (e^2-d f\right )\right )-c d e x\right ) \sqrt{a+c x^2}}{2 d^3}-\frac{\left (a+c x^2\right )^{3/2}}{2 d x^2}+\frac{e \left (a+c x^2\right )^{3/2}}{d^2 x}+\frac{(3 c) \operatorname{Subst}\left (\int \frac{\sqrt{a+c x}}{x} \, dx,x,x^2\right )}{4 d}-\frac{(3 a c e) \int \frac{1}{\sqrt{a+c x^2}} \, dx}{2 d^2}-\frac{\int \frac{3 a c e f^3 \left (c d^2+2 a \left (e^2-2 d f\right )\right )-3 c f^3 \left (2 c^2 d^3+a c d \left (3 e^2-4 d f\right )-2 a^2 f \left (e^2-d f\right )\right ) x-9 a c^2 d e f^4 x^2}{\sqrt{a+c x^2} \left (d+e x+f x^2\right )} \, dx}{6 c d^3 f^3}+\frac{\left (a \left (e^2-d f\right )\right ) \operatorname{Subst}\left (\int \frac{\sqrt{a+c x}}{x} \, dx,x,x^2\right )}{2 d^3}\\ &=\frac{3 c \sqrt{a+c x^2}}{2 d}+\frac{a \left (e^2-d f\right ) \sqrt{a+c x^2}}{d^3}-\frac{3 c e x \sqrt{a+c x^2}}{2 d^2}-\frac{\left (2 \left (c d^2+a \left (e^2-d f\right )\right )-c d e x\right ) \sqrt{a+c x^2}}{2 d^3}-\frac{\left (a+c x^2\right )^{3/2}}{2 d x^2}+\frac{e \left (a+c x^2\right )^{3/2}}{d^2 x}+\frac{(3 a c) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{a+c x}} \, dx,x,x^2\right )}{4 d}+\frac{(3 a c e) \int \frac{1}{\sqrt{a+c x^2}} \, dx}{2 d^2}-\frac{(3 a c e) \operatorname{Subst}\left (\int \frac{1}{1-c x^2} \, dx,x,\frac{x}{\sqrt{a+c x^2}}\right )}{2 d^2}-\frac{\int \frac{9 a c^2 d^2 e f^4+3 a c e f^4 \left (c d^2+2 a \left (e^2-2 d f\right )\right )+\left (9 a c^2 d e^2 f^4-3 c f^4 \left (2 c^2 d^3+a c d \left (3 e^2-4 d f\right )-2 a^2 f \left (e^2-d f\right )\right )\right ) x}{\sqrt{a+c x^2} \left (d+e x+f x^2\right )} \, dx}{6 c d^3 f^4}+\frac{\left (a^2 \left (e^2-d f\right )\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{a+c x}} \, dx,x,x^2\right )}{2 d^3}\\ &=\frac{3 c \sqrt{a+c x^2}}{2 d}+\frac{a \left (e^2-d f\right ) \sqrt{a+c x^2}}{d^3}-\frac{3 c e x \sqrt{a+c x^2}}{2 d^2}-\frac{\left (2 \left (c d^2+a \left (e^2-d f\right )\right )-c d e x\right ) \sqrt{a+c x^2}}{2 d^3}-\frac{\left (a+c x^2\right )^{3/2}}{2 d x^2}+\frac{e \left (a+c x^2\right )^{3/2}}{d^2 x}-\frac{3 a \sqrt{c} e \tanh ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a+c x^2}}\right )}{2 d^2}+\frac{(3 a) \operatorname{Subst}\left (\int \frac{1}{-\frac{a}{c}+\frac{x^2}{c}} \, dx,x,\sqrt{a+c x^2}\right )}{2 d}+\frac{(3 a c e) \operatorname{Subst}\left (\int \frac{1}{1-c x^2} \, dx,x,\frac{x}{\sqrt{a+c x^2}}\right )}{2 d^2}+\frac{\left (a^2 \left (e^2-d f\right )\right ) \operatorname{Subst}\left (\int \frac{1}{-\frac{a}{c}+\frac{x^2}{c}} \, dx,x,\sqrt{a+c x^2}\right )}{c d^3}-\frac{\left (c^2 d^3 \left (e-\sqrt{e^2-4 d f}\right )+2 a c d^2 f \left (e+\sqrt{e^2-4 d f}\right )+a^2 f \left (e^3-3 d e f+e^2 \sqrt{e^2-4 d f}-d f \sqrt{e^2-4 d f}\right )\right ) \int \frac{1}{\left (e-\sqrt{e^2-4 d f}+2 f x\right ) \sqrt{a+c x^2}} \, dx}{d^3 \sqrt{e^2-4 d f}}+\frac{\left (2 a c d^2 f \left (e-\sqrt{e^2-4 d f}\right )+c^2 d^3 \left (e+\sqrt{e^2-4 d f}\right )+a^2 f \left (e^3-3 d e f-e^2 \sqrt{e^2-4 d f}+d f \sqrt{e^2-4 d f}\right )\right ) \int \frac{1}{\left (e+\sqrt{e^2-4 d f}+2 f x\right ) \sqrt{a+c x^2}} \, dx}{d^3 \sqrt{e^2-4 d f}}\\ &=\frac{3 c \sqrt{a+c x^2}}{2 d}+\frac{a \left (e^2-d f\right ) \sqrt{a+c x^2}}{d^3}-\frac{3 c e x \sqrt{a+c x^2}}{2 d^2}-\frac{\left (2 \left (c d^2+a \left (e^2-d f\right )\right )-c d e x\right ) \sqrt{a+c x^2}}{2 d^3}-\frac{\left (a+c x^2\right )^{3/2}}{2 d x^2}+\frac{e \left (a+c x^2\right )^{3/2}}{d^2 x}-\frac{3 \sqrt{a} c \tanh ^{-1}\left (\frac{\sqrt{a+c x^2}}{\sqrt{a}}\right )}{2 d}-\frac{a^{3/2} \left (e^2-d f\right ) \tanh ^{-1}\left (\frac{\sqrt{a+c x^2}}{\sqrt{a}}\right )}{d^3}+\frac{\left (c^2 d^3 \left (e-\sqrt{e^2-4 d f}\right )+2 a c d^2 f \left (e+\sqrt{e^2-4 d f}\right )+a^2 f \left (e^3-3 d e f+e^2 \sqrt{e^2-4 d f}-d f \sqrt{e^2-4 d f}\right )\right ) \operatorname{Subst}\left (\int \frac{1}{4 a f^2+c \left (e-\sqrt{e^2-4 d f}\right )^2-x^2} \, dx,x,\frac{2 a f-c \left (e-\sqrt{e^2-4 d f}\right ) x}{\sqrt{a+c x^2}}\right )}{d^3 \sqrt{e^2-4 d f}}-\frac{\left (2 a c d^2 f \left (e-\sqrt{e^2-4 d f}\right )+c^2 d^3 \left (e+\sqrt{e^2-4 d f}\right )+a^2 f \left (e^3-3 d e f-e^2 \sqrt{e^2-4 d f}+d f \sqrt{e^2-4 d f}\right )\right ) \operatorname{Subst}\left (\int \frac{1}{4 a f^2+c \left (e+\sqrt{e^2-4 d f}\right )^2-x^2} \, dx,x,\frac{2 a f-c \left (e+\sqrt{e^2-4 d f}\right ) x}{\sqrt{a+c x^2}}\right )}{d^3 \sqrt{e^2-4 d f}}\\ &=\frac{3 c \sqrt{a+c x^2}}{2 d}+\frac{a \left (e^2-d f\right ) \sqrt{a+c x^2}}{d^3}-\frac{3 c e x \sqrt{a+c x^2}}{2 d^2}-\frac{\left (2 \left (c d^2+a \left (e^2-d f\right )\right )-c d e x\right ) \sqrt{a+c x^2}}{2 d^3}-\frac{\left (a+c x^2\right )^{3/2}}{2 d x^2}+\frac{e \left (a+c x^2\right )^{3/2}}{d^2 x}+\frac{\left (c^2 d^3 \left (e-\sqrt{e^2-4 d f}\right )+2 a c d^2 f \left (e+\sqrt{e^2-4 d f}\right )+a^2 f \left (e^3-3 d e f+e^2 \sqrt{e^2-4 d f}-d f \sqrt{e^2-4 d f}\right )\right ) \tanh ^{-1}\left (\frac{2 a f-c \left (e-\sqrt{e^2-4 d f}\right ) x}{\sqrt{2} \sqrt{2 a f^2+c \left (e^2-2 d f-e \sqrt{e^2-4 d f}\right )} \sqrt{a+c x^2}}\right )}{\sqrt{2} d^3 \sqrt{e^2-4 d f} \sqrt{2 a f^2+c \left (e^2-2 d f-e \sqrt{e^2-4 d f}\right )}}-\frac{\left (2 a c d^2 f \left (e-\sqrt{e^2-4 d f}\right )+c^2 d^3 \left (e+\sqrt{e^2-4 d f}\right )+a^2 f \left (e^3-3 d e f-e^2 \sqrt{e^2-4 d f}+d f \sqrt{e^2-4 d f}\right )\right ) \tanh ^{-1}\left (\frac{2 a f-c \left (e+\sqrt{e^2-4 d f}\right ) x}{\sqrt{2} \sqrt{2 a f^2+c \left (e^2-2 d f+e \sqrt{e^2-4 d f}\right )} \sqrt{a+c x^2}}\right )}{\sqrt{2} d^3 \sqrt{e^2-4 d f} \sqrt{2 a f^2+c \left (e^2-2 d f+e \sqrt{e^2-4 d f}\right )}}-\frac{3 \sqrt{a} c \tanh ^{-1}\left (\frac{\sqrt{a+c x^2}}{\sqrt{a}}\right )}{2 d}-\frac{a^{3/2} \left (e^2-d f\right ) \tanh ^{-1}\left (\frac{\sqrt{a+c x^2}}{\sqrt{a}}\right )}{d^3}\\ \end{align*}
Mathematica [C] time = 3.54652, size = 904, normalized size = 1.35 \[ \frac{\frac{6 c d^2 \, _2F_1\left (2,\frac{5}{2};\frac{7}{2};\frac{c x^2}{a}+1\right ) \left (c x^2+a\right )^{5/2}}{a^2}-5 \left (e^2-\frac{\left (e^2-3 d f\right ) e}{\sqrt{e^2-4 d f}}-d f\right ) \left (c x^2+a\right )^{3/2}-5 \left (e^2+\frac{\left (e^2-3 d f\right ) e}{\sqrt{e^2-4 d f}}-d f\right ) \left (c x^2+a\right )^{3/2}+\frac{30 a d e \, _2F_1\left (-\frac{3}{2},-\frac{1}{2};\frac{1}{2};-\frac{c x^2}{a}\right ) \sqrt{c x^2+a}}{x \sqrt{\frac{c x^2}{a}+1}}+\frac{15 \left (-e^2-\frac{\left (e^2-3 d f\right ) e}{\sqrt{e^2-4 d f}}+d f\right ) \left (\frac{2 \sqrt{c} \left (\sqrt{e^2-4 d f}-e\right ) \sqrt{c x^2+a} \left (\sqrt{c} \sqrt{\frac{c x^2}{a}+1} x+\sqrt{a} \sinh ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a}}\right )\right )}{\sqrt{\frac{c x^2}{a}+1}}+\frac{2 \left (2 a f^2+c \left (e^2-\sqrt{e^2-4 d f} e-2 d f\right )\right ) \left (2 \sqrt{c x^2+a} f+\sqrt{c} \left (\sqrt{e^2-4 d f}-e\right ) \tanh ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{c x^2+a}}\right )-\sqrt{2 c e^2-2 c \sqrt{e^2-4 d f} e+4 a f^2-4 c d f} \tanh ^{-1}\left (\frac{2 a f+c \left (\sqrt{e^2-4 d f}-e\right ) x}{\sqrt{4 a f^2-2 c \left (-e^2+\sqrt{e^2-4 d f} e+2 d f\right )} \sqrt{c x^2+a}}\right )\right )}{f^2}\right )}{8 f}-\frac{15 \left (-e^2+\frac{\left (e^2-3 d f\right ) e}{\sqrt{e^2-4 d f}}+d f\right ) \left (\frac{2 \sqrt{c} \left (e+\sqrt{e^2-4 d f}\right ) \sqrt{c x^2+a} \left (\sqrt{c} \sqrt{\frac{c x^2}{a}+1} x+\sqrt{a} \sinh ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{a}}\right )\right )}{\sqrt{\frac{c x^2}{a}+1}}+\frac{2 \left (2 a f^2+c \left (e^2+\sqrt{e^2-4 d f} e-2 d f\right )\right ) \left (-2 \sqrt{c x^2+a} f+\sqrt{c} \left (e+\sqrt{e^2-4 d f}\right ) \tanh ^{-1}\left (\frac{\sqrt{c} x}{\sqrt{c x^2+a}}\right )+\sqrt{4 a f^2+2 c \left (e^2+\sqrt{e^2-4 d f} e-2 d f\right )} \tanh ^{-1}\left (\frac{2 a f-c \left (e+\sqrt{e^2-4 d f}\right ) x}{\sqrt{4 a f^2+2 c \left (e^2+\sqrt{e^2-4 d f} e-2 d f\right )} \sqrt{c x^2+a}}\right )\right )}{f^2}\right )}{8 f}+10 \left (e^2-d f\right ) \left (\sqrt{c x^2+a} \left (c x^2+4 a\right )-3 a^{3/2} \tanh ^{-1}\left (\frac{\sqrt{c x^2+a}}{\sqrt{a}}\right )\right )}{30 d^3} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.312, size = 10298, normalized size = 15.4 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (c x^{2} + a\right )}^{\frac{3}{2}}}{{\left (f x^{2} + e x + d\right )} x^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \mathit{sage}_{2} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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